Thursday 10 October 2013

Representation of Integers as Sum of Squares

Sum of two squares: 


  • No integer of the form 4k + 3 is the sum of two squares.
  • If each m and n are sum of two squares, then there product mn is also a sum of two squares.
  • Thuw's lemma: Let p be a prime and a an integer, which is coprime to p. Then the linear congruence ax y (mod p) has the solution (x0, y0) such that                                              0 < |x0| < p and 0 < |y0| < p.
  • Fermat's lemma: An odd prime p can be represented as a sum of two squares iff ≡ 1 (mod 4).
  • A positive integer n > 1 can be represented as sum of two squares iff either n has no prime factor congruent to 3 (mod 4) or if it has a prime factor congruent to 3 (mod 4) then it occurs to an even power in the prime factorization of n.
  • Every odd prime is the difference of two squares in one and only one way.
Sum of three or more squares: 
  • Any integer of the form 4n (8m + 7) integers m, n  0 is not a sum of three squares.
  • If p is a prime number. Then there exist integers a, b, c atleast of which are non-zero such that  a2 + b2 + c2 0 (mod p)
  • Euler's lemma: If each of two positive integers and n is a sum of four squares, then their product mn is also a sum of four squares.
  • Any prime number p can be written as sum of four non-negative squares.
  • Legranges theorem: Every integer > 1 can be represented as the sum of four non-negative squares.
  • Aubry theorem: There are infinitely m any primes each of which is a sum of three distinct squares
Arithmetical function: A real or complex valued function defined on the positive integers is called an arithmetical function.

Mobius Function:
The Mobius function μ is defined as
                                    μ(1) = 1
     If  n > 1, write n = p1a1 … pkak then 
                                    μ(n) = (-1)k if a1 = a2 = … = ak = 1
                                    μ(n) = 0, otherwise.

  • μ(n) = 0 iff n has a square factor > 1.
  • If n ≥ 1, we have
                                   μ(d) = [1/n]

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